Primality proof for n = 61:
Take b = 2.
b^(n-1) mod n = 1.
5 is prime.
b^((n-1)/5)-1 mod n = 8, which is a unit, inverse 23.
3 is prime.
b^((n-1)/3)-1 mod n = 46, which is a unit, inverse 4.
(3 * 5) divides n-1.
(3 * 5)^2 > n.
n is prime by Pocklington's theorem.