Primality proof for n = 4003:
Take b = 2.
b^(n-1) mod n = 1.
29 is prime.
b^((n-1)/29)-1 mod n = 3778, which is a unit, inverse 1192.
23 is prime.
b^((n-1)/23)-1 mod n = 3064, which is a unit, inverse 1961.
(23 * 29) divides n-1.
(23 * 29)^2 > n.
n is prime by Pocklington's theorem.