Primality proof for n = 257:
Take b = 3.
b^(n-1) mod n = 1.
2 is prime. b^((n-1)/2)-1 mod n = 255, which is a unit, inverse 128.
(2^8) divides n-1.
(2^8)^2 > n.
n is prime by Pocklington's theorem.