Primality proof for n = 19813:
Take b = 2.
b^(n-1) mod n = 1.
127 is prime.
b^((n-1)/127)-1 mod n = 70, which is a unit, inverse 6510.
13 is prime.
b^((n-1)/13)-1 mod n = 9354, which is a unit, inverse 10292.
(13 * 127) divides n-1.
(13 * 127)^2 > n.
n is prime by Pocklington's theorem.