Primality proof for n = 1613:
Take b = 2.
b^(n-1) mod n = 1.
13 is prime.
b^((n-1)/13)-1 mod n = 125, which is a unit, inverse 942.
2 is prime.
b^((n-1)/2)-1 mod n = 1611, which is a unit, inverse 806.
(2^2 * 13) divides n-1.
(2^2 * 13)^2 > n.
n is prime by Pocklington's theorem.